How do you solve #abs(8x) > 20#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Alberto M. May 3, 2015 The answer is #x>5/2 or x<-5/2# #abs(8x)=8abs(x) => abs(8x)>20 <=> 8abs(x)>20 <=> abs(x)>5/2 <=> x>5/2 or x<-5/2# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1378 views around the world You can reuse this answer Creative Commons License