# How do you solve abs(8x) > 20?

The answer is $x > \frac{5}{2} \mathmr{and} x < - \frac{5}{2}$
$\left\mid 8 x \right\mid = 8 \left\mid x \right\mid \implies \left\mid 8 x \right\mid > 20 \iff 8 \left\mid x \right\mid > 20 \iff \left\mid x \right\mid > \frac{5}{2} \iff x > \frac{5}{2} \mathmr{and} x < - \frac{5}{2}$