How do you solve #abs(-8x + 4)= 6x + 8#?

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Answer 1 · 2018-06-03T15:40:21

#x=6# or #x=-2/7#

Writing your equation in the form
#2|-4x+2|=2(3x-4)#
so we have
#|-4x+2|=3x+4#
or

#|4x-2|=3x+4#
If we have #x>=1/2#
so we get
#4x-2=3x+4#
so #x=6#

In the case that #x<1/2# we get

#-4x+2=3x+4#

we get

#7x=-2#

so #x=-2/7#