# How do you solve abs(c-3)=1?

$\textcolor{red}{c - 3 = 1} \text{ or } \textcolor{b l u e}{- \left(c - 3\right) = 1}$
$\Rightarrow \textcolor{red}{c = 1 + 3 = 4} \text{ or"color(blue)(-c+3=1)"thus } \textcolor{b l u e}{c = 3 - 1 = 2}$