How do you solve abs(k-10)=3?

Feb 25, 2017

$k = 7 , k = 13$

Explanation:

$| k - 10 | = 3$ is really two problems:

$+ \left(k - 10\right) = 3$ and $- \left(k - 10\right) = 3$

Solve each one:
$k - 10 = 3$
$k - 10 + 10 = 10 + 3$
$k = 13$

$- \left(k - 10\right) = 3$
$- k + 10 = 3$
$- k + 10 - 10 = 3 - 10$
$- k = - 7$
$k = 7$