# How do you solve abs(k-8)=0?

Aug 2, 2015

$k = 8$

#### Explanation:

The absolute value function does nothing here.

Usually if you remove a abs function, you put $\pm$ on the other side of the equation. But $\pm 0 = 0$. So,

 abs( k − 8 ) = 0
$\implies k - 8 = \pm 0 = 0$
# => k = 8

You can verify this by drawing the graph of the function $f \left(x\right) = \left\mid x - 8 \right\mid$ and noting that the point where it meets the x-axis is unique.