How do you solve #-abs(x+1)=-2#?
1 Answer
The answer is:
The way to solve it is as follows.
Equal parts of an equation, left and right, can be multiplied by the same non-equal to zero multiplier getting an equivalent equation.
Let's multiply them by
Now we have to remember the definition of the absolute value of a number.
If the number is positive or zero, its absolute value equals to itself:
if
If the number is negative, its absolute value equals to its opposite (or, not very scientifically, minus this number)
if
Applying this to a problem at hand:
CASE 1
Looking for solutions in the area defined by an inequality
using our equation,
This value is within the area
CASE 2
Looking for solutions in the area defined by an inequality
using our equation,
This value is within the area
We can demonstrate it graphically.
Our equation is equivalent to
Let's draw a graph of a function
graph{|x+1|-2 [-10, 10, -5, 5]}
As you see, it intersects the X-axis (that is, equals to zero) at points