Question

How do you solve `-abs(x+1)=-2`?

Answer 1

`x=1`
or
`x=-3`

Explanation:

If `-abs(x+1) = -2` then
`color(white)("XXXX")` `abs(x+1) = 2`

Case 1: `x+1>=0`
In this case `abs(x+1) = 2`

`rArr x=1`

Case 2: `(x+1) < 0`
In this case `abs(x+1) = 2`
is the same as `(-x-1) = 2`
`rArr x=-3`