How do you solve #abs(x+1)<3#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Shwetank Mauria Sep 2, 2016 #-4 < x <2# Explanation: As #|x+1|<3#, we have either #x+1<3# i.e. #x<2# or #-(x×1)<3# i.e. #0 < x+1+3# or #x > -4# Hence solution is #-4 < x < 2# Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 2003 views around the world You can reuse this answer Creative Commons License