Question

How do you solve `absp= 0`?

Answer 1

`p = 0`

Explanation:

`abs(a) = a` if `a >= 0`

`abs(a) = -a` if `a <= 0`

So if `abs(a) = b`, then `b >= 0` and `a = +-b`

In our example `abs(p) = 0` means `p = +-0 = 0`