# How do you solve and check for extraneous solutions in #4/v + 1/5 = 1#?

##### 1 Answer

Aug 14, 2015

Isolate the term containing the variable; multiply to clear the denominators and divide by the constant to get

#### Explanation:

Given

Subtract

(At this point it should be obvious that

Multiply both sides by

Divide by

Verify that this is not an extraneous solution by substituting