# How do you solve and check for extraneous solutions in #abs(2x + 3) = 5#?

##### 2 Answers

Solve: |2x + 3| = 5

Ans : x = 1, x = - 4

#### Explanation:

separate solving in 2 cases:

a. (2x + 3) = 5 --> 2x = 2 -->

b. - (2x + 3 ) = 5 --> -2x - 3 = 5 --> -2x = 8 -->

There are

#### Explanation:

**SOLVE**

We need to write two different equations without the absolute value symbols and solve for

These equations are

**(1): **

**(2): **

**Solve Equation 1:**

Subtract

Divide each side by

**Solve Equation 2:**

Remove parentheses.

Add

Divide each side by

The solutions are

**CHECK FOR EXTRANEOUS SOLUTIONS:**

If

If

There are no extraneous solutions.