How do you solve and find the ordered pairs #1/2 x - 2y = 4 and 4y - x = -8#?

1 Answer
Aug 18, 2017

Answer:

Using #x = 4y+8" "# if you choose values of #y# you can find the corresponding values of #x# and hence obtain the ordered pairs.

Explanation:

The first equation can be changed into a better form by removing the fraction:

#2xx1/2x-2xx2y =2xx4" "xx# each term by #2#

#x-4y = 8#

the second equation can be rewritten as #x-4y =8#

We therefore see that there is actually only one equation, and as it has two variables, there are many solutions.

Using #x = 4y+8" "# if you choose values of #y# you can find the corresponding values of #x# and hence obtain the ordered pairs.

#y=0, rarr x=8" "rarr (8,0)#
#y=1, rarr x=12" "rarr (12,1)#
#y=2, rarr x=16" "rarr (16,2)#
#y=-1, rarr x=4" "rarr (4,-1)#
#y=-2, rarr x=0" "rarr (0,-2)#

IN this way you can generate as many ordered pairs as you need.