Question

How do you solve and find the value of `cos(cos^-1(2/9))`?

Answer 1

`0.222222222` or `2/9`

Explanation:

`cos(cos^-1(2/9))`

`:.=cos(arccos(0.222222222)`

`:.=cos(77.16041159)rarr` decimals of a degree`rarr77°09'37.48''`

`:.=0.222222222rarr 2/9`