# How do you solve and graph abs(x+1)<0?

Oct 29, 2017

No solutions
graph{abs(x+1) [-10, 10, -5, 5]}

#### Explanation:

We can note that $| a | \ge 0 , | a |$ is never negative for all real $a$, so hence $| x + 1 |$ is never negative, hence no solutions to $| x + 1 | < 0$.

To sketch this graph, we can consider $y = x + 1$
graph{y = x+1 [-10, 10, -5, 5]}

Then as we know $| a | \ge 0$ for all real a, we just take the graph in the domain where the function is negative, and reflect in the x axis, so for $x < - 1$ we make possitive, yielding;

graph{|x+1| [-10, 10, -5, 5]}

We can see clearly from this that $| x + 1 |$ is never negative