How do you solve and write the following in interval notation: #1/4x-2≤-1#?

1 Answer
Jun 22, 2016

Answer:

#x<=4.#
In the interval notation, this is #(-oo,4].#

Explanation:

Given that, #1/4x-2<=-1#

Adding 2, we get, #1/4x<=2-1=1,# i,e., #1/4x<=1.#

We now multiply by #4#. As #4# is #+ve#, we note that this will have no effect on the order of inequality. Hence, #x<=4.#

In the interval notation, this is written as #(-oo,4].#