How do you solve and write the following in interval notation: #1/4x+3>=4-1/3x#?
1 Answer
Feb 15, 2017
Explanation:
Multiply ALL terms on both sides of the inequality by 12, the LCM of 4 and 3
#(cancel(12)^3xxx/cancel(4)^1)+(12xx3)>=(12xx4)-(cancel(12)^4xx x/cancel(3)^1)#
#rArr3x+36>=48-4x# collect terms in x on the left side and numeric values on the right side.
add 4x to both sides.
#3x+4x+36>=48cancel(-4x)cancel(+4x)#
#rArr7x+36>=48# subtract 36 from both sides.
#7xcancel(+36)cancel(-36)>=48-36#
#rArr7x>=12#
#(cancel(7) x)/cancel(7)>=12/7#
#rArrx>=12/7" is the solution"#
#"expressed in interval notation "[12/7,+oo)#