How do you solve and write the following in interval notation: #-10<b/2<0#?

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Answer 1 · 2017-04-21T02:43:58

See the entire solution process below:

First, multiply each segment of the system of inequalities by #color(red)(2)# to solve for #b# while keeping the system balanced:

#color(red)(2) * -10 < color(red)(2) * b/2 < color(red)(2) * 0#

#-20 < cancel(color(red)(2)) * b/color(red)(cancel(color(black)(2))) < 0#

#-20 < b < 0#

Or

#b > -20# and #b < 0#

Or

#(-20, 0)#