How do you solve and write the following in interval notation: #-12<8-x<=-7 #?

1 Answer
Aug 19, 2017

Answer:

See explanation.

Explanation:

#-12 < 8-x < -7#

First you subtract #8# from all sides.

#-20 < -x < -15#

Next step is to multiply all sides by #-1# with changing the inequality sign from #<# to #>#

#20 > x > 15#

Finally you can write the solution in an interval form:

#x in (15;20)#