# How do you solve and write the following in interval notation: 16<9/2a+(-2) ?

Aug 23, 2017

Solution: $a > 4$ , in interval notation : $\left(4 , \infty\right)$
$16 < \frac{9}{2} a + \left(- 2\right) \mathmr{and} 16 + 2 < \frac{9}{2} a \mathmr{and} 18 < \frac{9}{2} a$ or
$18 \cdot \frac{2}{9} < a \mathmr{and} 4 < a \mathmr{and} a > 4$
Solution: $a > 4$ , in interval notation :$\left(4 , \infty\right)$ [Ans]