# How do you solve and write the following in interval notation: -2 abs(s-3) <-4?

Mar 28, 2017

Solution: $s < 1 \mathmr{and} s > 5$. In interval notation: $\left(- \infty , 1\right) \cup \left(5 , \infty\right)$
$- 2 | s - 3 | < - 4 \mathmr{and} - | s - 3 | < - 2 \mathmr{and} | s - 3 | > 2 \mathmr{and} s - 3 > 2 \mathmr{and} s > 5$ OR
$- 2 | s - 3 | < - 4 \mathmr{and} - | s - 3 | < - 2 \mathmr{and} | s - 3 | > 2 \mathmr{and} s - 3 < - 2 \mathmr{and} s < 1$
Solution: $s < 1 \mathmr{and} s > 5$. In interval notation: $\left(- \infty , 1\right) \cup \left(5 , \infty\right)$[Ans]