How do you solve and write the following in interval notation: #-2 abs(s-3) <-4#?

1 Answer
Mar 28, 2017

Answer:

Solution: # s <1 or s >5#. In interval notation: #(-oo , 1) uu (5 , oo)#

Explanation:

#-2 |s-3| < -4 or - | s-3 | < -2 or |s-3| > 2 or s-3 >2 or s > 5 # OR

#-2 |s-3| < -4 or - | s-3 | < -2 or |s-3| > 2 or s-3 < -2 or s < 1 #

Solution: # s <1 or s >5#. In interval notation: #(-oo , 1) uu (5 , oo)#[Ans]