How do you solve and write the following in interval notation: #4 ≤ 3 − x <8#?
1 Answer
Aug 7, 2017
Explanation:
#"isolate x in the middle interval by subtracting 3 from all 3"#
#"intervals"#
#4-3<=3-3-x<8-3#
#rArr1<=-x<5#
#"multiply all 3 intervals by - 1 remembering to reverse the"#
#"inequality signs"#
#rArr-1>=x> -5larrcolor(red)" reverse signs"#
#"in interval notation as "(-5,-1]#
