# How do you solve and write the following in interval notation: -5(2x+3) >3?

Jul 20, 2016

$x < - \frac{9}{5}$

$\left(- \infty , - \frac{9}{5}\right)$

#### Explanation:

Distribute the $- 5$ across the parenthesis.

$- 5 \left(2 x\right) + - 5 \left(3\right) > 3$

$- 10 x - 15 > 3$

Add $15$ to both sides and isolate $x$.

$- 10 x \cancel{- 15 + 15} > 3 + 15$

$- 10 x > 18$

Divide by $- 10$ and remember to switch the sign.

$\frac{\cancel{- 10} x}{\cancel{- 10}} < \frac{18}{-} 10$

$x < - \frac{18}{10}$

Simplify $- \frac{18}{10}$.

$x < - \frac{9}{5}$

Now write in interval notation:

$\left(- \infty , - \frac{9}{5}\right)$