How do you solve and write the following in interval notation: #- 5<a -6<2#?

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Answer 1 · 2017-06-29T18:42:53

See a solution process below:

Add #color(red)(6)# to each segment of the system of inequalities to solve for #a# while keeping the equation balanced:

#-5 + color(red)(6) < a - 6 + color(red)(6) < 2 + color(red)(6)#

#1 < a - 0 < 8#

#1 < a < 8#

Or

#a > 1# and #a < 8)#

Or, in interval notation:

#(1, 8)#