How do you solve and write the following in interval notation: #8- 5x<=23#?

1 Answer
May 25, 2017

Answer:

#[-3,+oo)#

Explanation:

#"Isolate " -5x" by subtracting 8 from both sides"#

#cancel(8)cancel(-8)-5x<=23-8#

#rArr-5x<=15#

#"divide both sides by - 5"#

#color(blue)"Note ""when multiplying/dividing an inequality"#
#"by a negative quantity, the inequality sign is "color(red)"reversed"#

#(cancel(-5) x)/cancel(-5)>=15/(-5)larrcolor(red)" reverse sign"#

#rArrx>=-3" is the solution"#

#[-3,+oo)larr" in interval notation"#