How do you solve and write the following in interval notation: #x - 2 ≤ 0# or #x - 1 ≥ 3#?

1 Answer
Aug 16, 2017

Answer:

Solution : (1) #x <= 2 or (-oo,2] #, (2) # x >= 4 or [4, oo) #

Explanation:

# x -2 <= 0 or x <= 2 # , In interval notation #x# is expressed as

# (-oo,2] #, means #x# is any quantity from #-oo# to #2#(inclusive).

# x -1 >= 3 or x >= 4 # , In interval notation #x# is expressed as

# [4, oo) #, means #x# is any quantity from #4#(inclusive) to #oo#.

Solution : (1) #x <= 2 or (-oo,2] #, (2) # x >= 4 or [4, oo) # [Ans]