How do you solve $(b+1)/3=2$ ?

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Answer 1 · 2018-03-11T14:34:47

$b=5$

We got: $(b+1)/3=2$

Multiplying both sides by $3$ , we get

$color(red)cancelcolor(black)3*(b+1)/(color(red)cancelcolor(black)3)=2*3$

$b+1=6$

Subtracting $1$ from both sides, we have

$b+color(red)cancelcolor(black)1-color(red)cancelcolor(black)1=6-1$

$b=5$

Answer 2 · 2018-03-11T14:35:12

$b = 5$

$(b+1)/3 =2$

Cross multiply

$b+1 = (2)(3)$

$b+1 = 6$

Subtract $1$ on both sides

$b + 1 - 1 = 6 - 1$

$b = 5$

How do you solve (b+1)/3=2(b+1)/3=2?