# How do you solve (b+2)^2 = 4?

Mar 28, 2018

$b = 0$

#### Explanation:

Take the square root of both sides to eliminate the square:

$\sqrt{{\left(b + 2\right)}^{2}} = \sqrt{4}$

so you get:

$b + 2 = 2$

$b = 0$