How do you solve #(b+2)/3 - (b-2)/7=2#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Binayaka C. Apr 22, 2018 Solution: #b=5 1/2# Explanation: #(b+2)/3- (b-2)/7=2# . Multiplying by #21# on both sides we get, #7(b+2)- 3(b-2)=42# or #7 b+14- 3 b +6=42# or #4 b=22 :. b= 22/4= 11/2 = 5 1/2# Solution: #b=5 1/2# [Ans] Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1525 views around the world You can reuse this answer Creative Commons License