# How do you solve by completing the square #3x^2 + 6x +12 = 0#?

##### 1 Answer

Mar 30, 2015

First divide both sides of the equation by the coefficient of

If

then

Rewrite the left-side of the expression as

This can not be solved with any real number value for

as can be seen from the graph of the original equation below (it never is equal to

graph{3x^2+6x+4 [-16.03, 16, -1.31, 14.71]}

However, if we allow complex solutions