# How do you solve by completing the square: #x^2 + 8x + 2 = 0#?

##### 2 Answers

The answer is

The general form of a trinomial is

**Solve the trinomial #x^2+8x+2=0#**

First move the constant to the right side by subtracting 2 from both sides.

Divide only the coefficient of 8x by 2. Square the result, and add that value to both sides of the equation.

The left side is now a perfect square trinomial. Factor the perfect square trinomial.

Take the square root of each side and solve.

Source:

http://www.regentsprep.org/regents/math/algtrig/ate12/completesqlesson.htm

The answer is

The general form of a trinomial is

**Solve the trinomial #x^2+8x+2=0#**

First move the constant to the right side by subtracting 2 from both sides.

Divide only the coefficient of 8x by 2. Square the result, and add that value to both sides of the equation.

The left side is now a perfect square trinomial. Factor the perfect square trinomial.

Take the square root of each side and solve.

Source:

http://www.regentsprep.org/regents/math/algtrig/ate12/completesqlesson.htm