How do you solve by completing the square #(x -2) (x + 3)= x - 10#?

2 Answers
Mar 6, 2018

Answer:

#x=+-2i#

Explanation:

Given: #(x-2)(x+3)=x-10#

#color(brown)("Consider just the left hand side (LHS)")#

#color(blue)((x-2))color(green)( (x+3) )#

Multiply everything in the right brackets by everything in the left.

#color(green)(color(blue)(x)(x+3) color(white)("ddd")color(blue)(-2)(x+3) ) larr# Notice the minus followed the 2

#color(green)(x^2+ubrace(3xcolor(white)("dddd")-2x)-6)#

#color(green)(x^2color(white)("dddddd")+xcolor(white)("ddd")-6)#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(brown)("Putting it all back together")#

#color(white)("dd")"LHS"color(white)("ddddd")=color(white)("ddd")"RHS"#
#x^2+x-6color(white)("dd")=color(white)("dd")x-10#

As #x# is on both sides we can cancel them out.

#x^2+cancel(x)-6color(white)("dd")=color(white)("dd")cancel(x)-10#

Add 10 to both sides

#x^2+4=0#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(brown)("Completing the square")# ( If they insist !!!)

Write as #x^2+0x+4=0#

#(x+0/2)^2+4=0#

#(x+0/2)^2=-4#

Square root both sides

#x+0/2=+-sqrt(-4)#

#x=+-sqrt(4xx(-1))#

#x=+-2i#

Mar 6, 2018

Answer:

This solution is irrational. See below...

Explanation:

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Hope this helps!