How do you solve by completing the square #x=sqrt(x+13)+7#?
1 Answer
Apr 2, 2015
x=3; x=12
Rewrite it as x-7=
(x-
x-
x=
x= 12 or 3
x=3; x=12
Rewrite it as x-7=
(x-
x-
x=
x= 12 or 3