# How do you solve by using the quadratic formula: #x^2 + 7x = -3#?

##### 1 Answer

May 9, 2016

#x=-7/2+-sqrt(37)/2#

#### Explanation:

First add

#x^2+7x+3 = 0#

This is in the form

The roots are given by the quadratic formula:

#x = (-b+-sqrt(b^2-4ac))/(2a)#

#=(-7+-sqrt(7^2-(4*1*3)))/(2*1)#

#=(-7+-sqrt(49-12))/2#

#=(-7+-sqrt(37))/2#

#=-7/2+-sqrt(37)/2#

Note that since

#sqrt(37) = [6;bar(12)] = 6+1/(12+1/(12+1/(12+1/(12+1/(12+...)))))#