Question

How do you solve cot x >0 for x?

Answer 1

`(0, pi/2) and (pi, (3pi)/2)`

Explanation:

On the unit circle , cot > 0, when
`0 < x < pi/2`, and `pi < x < (3pi)/2`
Solution set by open intervals:
`(0, pi/2) and (pi, (3pi)/2)`