Question

How do you solve `csc((19pi)/4)=sqrt2`?

Answer 1

Trig table of special arcs and unit circle give:
`sin ((19pi)/4) = sin ((3pi)/4 + 4pi) = sin ((3pi)/4) = sqrt2/2`
Therefore:
`csc ((18pi)/4) = 1/(sin ((3pi)/4)) = 2/sqrt2 = sqrt2`. Proved.