Question

How do you solve d/dx (ln x)?

Answer 1

`d/dx lnx=1/x`

Explanation:

A fundamentally import calculus result is that `d/dxe^x=e^x`

Let `y=lnx <=> x=e^y`

Differentiate wrt `y`
`dx/dy = e^y` (using above result)
`:. dx/dy = x`
`:. dy/dx = 1/x` (By the chain rule)