How do you solve #e ^(2x + 1) = pi#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer mason m Dec 14, 2015 #x=(lnpi-1)/2# Explanation: Take the natural log of both sides. #ln(e^(2x+1))=lnpi# #2x+1=lnpi# #x=(lnpi-1)/2# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1370 views around the world You can reuse this answer Creative Commons License