How do you solve $e^{4 - 2 x} = 45$ $e^(4-2x) = 45$ ?

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Answer 1 · 2018-08-11T22:52:11

$e^{4 - 2 x} = 45$ $e^{4-2x}=45$

$ln (e^{4 - 2 x}) = ln 45$ $ln(e^{4-2x})=ln 45$

$4 - 2 x = ln 45$ $4-2x=ln45$

$- 2 x = ln 45 - 4$ $-2x=ln45-4$

$2 x = 4 - ln 45$ $2x=4-ln45$

$x = \frac{4 - ln 45}{2}$ $x=\frac{4-ln45}{2}$

How do you solve e^(4-2x) = 45e4−2x=45e^(4-2x) = 45?