How do you solve #e^(5x + 1) = 40#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan P. Oct 23, 2015 #x ~= 0.53778# Explanation: Given #color(white)("XXX")e^(5x+1) = 40# Therefore #color(white)("XXX")5x+1 = ln(40)# Using a calculator: #ln(40) ~= 3.6889# #color(white)("XXX")5x+1 ~= 3.6889# #color(white)("XXX")x ~= 0.53778# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2217 views around the world You can reuse this answer Creative Commons License