# How do you solve #e^x=0#?

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George C.
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Jun 30, 2016

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There is no

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The function

So it can only take strictly positive values.

When we consider

That is

Note that

We have already noted that iof

For pure imaginary exponents the result is on the unit circle, specifically:

#e^(yi) = cos y + i sin y != 0#

So

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