How do you solve $(e^(x+5) / e^(5)) = 3$ ?

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Answer 1 · 2018-05-23T12:44:05

Solution: $x= 1.0986$

$e^(x+5)/e^5=3 or( e^x *cancel (e^5))/cancel(e^5)=3$ or

$e^x =3$ Taking natural log on both sides we get,

$x ln e = ln 3 or x = ln 3 [ln e=1] :. x ~~ 1.0986 (4 dp)$

Solution: $x= 1.0986$ [Ans]

Answer 2 · 2018-06-08T03:24:07

$x~~1.10$

On the left side, we have the same bases, so we can subtract the exponents.

$(e^color(red)((x+5))/(e^color(blue)5))=e^(color(red)(x+5)-color(blue)5)=color(darkblue)(e^x)$

We now have the equation

$e^x=3$

The natural log ( $ln$ ) function cancels with base- $e$ , so we can take the natural log of both sides. We get

$cancel(ln)cancele^x=ln3$

$=>x=ln3$

$x~~1.10$

Hope this helps!

How do you solve (e^(x+5) / e^(5)) = 3(e^(x+5) / e^(5)) = 3?