How do you solve #(f-16)(f-27)=0#?

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Answer 1 · 2017-02-17T13:52:02

See the entire solution process below:

To solve this problem you equate each term in parenthesis to #0#:

Solution 1)

#f - 16 = 0#

#f - 16 + color(red)(16) = 0 + color(red)(16)#

#f - 0 = 16#

#f = 16#

Solution 2)

#f - 27 = 0#

#f - 27 + color(red)(27) = 0 + color(red)(27)#

#f - 0 = 27#

#f = 27#

The solution is: #f = 16# and #f = 27#