# How do you solve for all solutions, including complex solutions, to #(x + 14)^2 = 21 #?

##### 1 Answer

Mar 12, 2017

There are no complex solutions.

#### Explanation:

By squaring a monomial, we will get a quadratic. Thus, we have two solutions to the equation.

By taking the square root of both sides, we find that

Then, our answer comes after subtracting