# How do you solve for b given h = -16t^2 + b?

Apr 14, 2017

See the solution process below:

#### Explanation:

Add $\textcolor{red}{16 {t}^{2}}$ to each side of the equation to solve for $b$ while keeping the equation balanced:

$\textcolor{red}{16 {t}^{2}} + h = \textcolor{red}{16 {t}^{2}} - 16 {t}^{2} + b$

$16 {t}^{2} + h = 0 + b$

$16 {t}^{2} + h = b$

$b = 16 {t}^{2} + h$