# How do you solve for C: F=9/5C + 32?

Given $F = \frac{9}{5} C + 32$
$F - 32 = \frac{9}{5} C$
$\frac{5}{9} \left(F - 32\right) = C$
$C = \frac{5}{9} \left(F - 32\right)$