# What is the perimeter of the rectangle if the area of a rectangle is given by the formula A=l(w) and a rectangle has an area of 132 square centimeters and a length of 11 centimeters?

Nov 2, 2014

$A = l w = 132$

since $l = 11$,

$\implies 11 w = 132$

by dividing by $11$,

$\implies w = \frac{132}{11} = 12$

Hence, the perimeter $P$ can be found by

$P = 2 \left(l + w\right) = 2 \left(11 + 12\right) = 46$ cm

I hope that this was helpful.