# How do you solve for d in #n= (dh)/(f+d)#?

##### 1 Answer

Jul 17, 2016

#### Explanation:

To solve for

#n = (dh)/(f+d)#

#(f+d)/1 * n/1 = (dh)/cancel(f+d) * cancel(f+d)/1#

#((f+d)timesn) = dh#

#nf + nd = dh#

Now get all terms with

#nf = dh-nd#

#nf = d(h-n)#

Finish isolating the variable by getting

#(nf)/(h-n) = (d(cancel(h-n)))/cancel(h-n)#

#color(green)((nf)/(h-n) = d)#

This is your final answer.