Question

How do you solve for Hubble's constant?

Answer 1

If a galaxy is at a distance of P parsec, the angular spacing of its span will be P''. Observe the same galaxy 1 year later, for the angular span Q''. Now, see the explanation..

Explanation:

If a galaxy is at a distance of P parsec, the angular spacing of its span will be P''. Observe the same galaxy 1 year later, for the angular span Q''. Q is just very little over P

Now, the relative measure `H_0=(Q-P)/P` parsec/year/parsec.

It is easy to see that the dimension of `H_0` is `T^(-1)`.

From different sources, this is estimated to be 68 or 70 or 71 or 72 in standardized units km/s/mega parsec.

I have found reciprocals `{1/H_0}` of dimension T, in befitting units for parity. for age of our universe as 14.4 billion years (by), 14.0 by, 13.8 by and 13.6 by, respectively.

`H_0` is a measure for radial expansion,

The lateral (span) expansion of galaxy/cluster observed is `(Q-P)` AU/ year = (Q-P)/P AU/year/AU.. This follows from the definition of parsec. Note that `(Q-P)/P` is dimensionless.,

The purpose of making this note here is to convey what I have understood about `H_0` and related natters.. . . .