# How do you solve for Hubble's constant?

May 10, 2016

If a galaxy is at a distance of P parsec, the angular spacing of its span will be P''. Observe the same galaxy 1 year later, for the angular span Q''. Now, see the explanation..

#### Explanation:

If a galaxy is at a distance of P parsec, the angular spacing of its span will be P''. Observe the same galaxy 1 year later, for the angular span Q''. Q is just very little over P

Now, the relative measure ${H}_{0} = \frac{Q - P}{P}$ parsec/year/parsec.

It is easy to see that the dimension of ${H}_{0}$ is ${T}^{- 1}$.

From different sources, this is estimated to be 68 or 70 or 71 or 72 in standardized units km/s/mega parsec.

I have found reciprocals $\left\{\frac{1}{H} _ 0\right\}$ of dimension T, in befitting units for parity. for age of our universe as 14.4 billion years (by), 14.0 by, 13.8 by and 13.6 by, respectively.

${H}_{0}$ is a measure for radial expansion,

The lateral (span) expansion of galaxy/cluster observed is $\left(Q - P\right)$ AU/ year = (Q-P)/P AU/year/AU.. This follows from the definition of parsec. Note that $\frac{Q - P}{P}$ is dimensionless.,

The purpose of making this note here is to convey what I have understood about ${H}_{0}$ and related natters.. . . .