How do you solve for L in T = 2 π √ L g ?

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Mar 8, 2018

Answer:

#L=(gT^2)/(4pi^2)#

Explanation:

As #T=2pisqrt(L/g)#

#T^2=4pi^2xxL/g#

or #T^2xxg/(4pi^2)=4pi^2xxL/gxxg/(4pi^2)#

or #(gT^2)/(4pi^2)=L#

Hence #L=(gT^2)/(4pi^2)#

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