How do you solve for r in #1/2r +3s=1#?

1 Answer
Jun 23, 2016

Answer:

#color(blue)(r= 2 - 6s#

Explanation:

#1/2color(blue)(r) +3s = 1#

#1/2color(blue)(r)= 1 - 3s #

The main goal here is to isolate #color(blue)(r).#

#color(blue)(r)= (1 - 3s) xx color(green)(2)/1#

#color(blue)(r)= (1 ) xx color(green)(2) + (- 3s) xx color(green)( 2#

#color(blue)(r= 2 - 6s#